Solutions English 25 Created on July 13, 2023 By Arvind SirSolution English 1 / 35Unit of Molarity Mole per litre Mole per Kg Gram None of these 2 / 35A 5% solution of cane sugar (Mol. Wt=342) Is isotonic with 1% solution of substance X.The molecular weight of X is- 68.4 34.2 171.2 136.2 3 / 35Azeotropic mixture of HCl and H2O has- 48% HCl 22.2% HCl 36% HCl 20.2% HCl 4 / 35A solution has an osmotic pressure of 0.0821 atm at 300 K. Its concentration would be 0.66 M 0.32 M 0.066 M 0.0033 M 5 / 35Azeotropes are liquid mixtures which distil unchanged in composition liquids which can mix with each other in all proportions Solids which form solid solutions of definite composition gases which can be separated 6 / 35The normality of 0.3 M phosphorous, acid (H3PO3) is – 0.1 0.9 0.3 0.6 7 / 35The Van’t Hoff factor for 0.1 M Ba (NO3)2solution is 2.74. The degree of Dissociation is – 91.3% 87% 100% 74% 8 / 35Increasing the temperature of an aqueous solution will causes- decrease in molality decrease in molarity decrease in mole fraction decrease in % (w/w) 9 / 35If a is the degree of dissociation of Na2SO4, the vant Hoff’s factor (i) used for calculating the molecular mass is- 1 – a 1 + a 1 – 2a 1 + 2a 10 / 35which one of the following aqueous solutions will exhibit highest boiling point 0.01 M Na2SO4 0.001 M KNO3 0.015 M urea 0.015 M glucose 11 / 35Which of the following concentration factor is affected bu change intemperature Molarity Molality Mol fraction Weight fraction 12 / 35The osmotic pressure of equimolar solution of urea, BaCI2 and AICI3 will be in the order- AICI3>BaCI2>Urea BaCI2>AICI3>Urea Urea >BaCI2>AICI3 BaCI2>Urea >AICI3 13 / 35The molar elevation constant is the ratio of the elevation in BP to – Molarity Molality Mole fraction of solute Mole fraction of solvent 14 / 35The solution having some osmotic pressure at constant (given) temperature are called- Equivalent solutions Ideal solutions Equimolar solutions Isotonic solutions 15 / 35The osmotic pressure of 0.2 molar solution of urea at 300 K(R = 0.082 litreatm mol-1K-1) is- 4.92 atm 1 atm 0.25 atm 27 atm 16 / 35The osmotic pressure of a solution is given by the relation- π= RT/C π= CT/R π= RC/T π/C=RT 17 / 35In case of electrolyte which dissociates in solution the Vant Hoff’s factor- >unity <Unity =Unity Can be>or<1 18 / 35The Vant Hoff factor (i) for a dilute aqueous solution of glucose is- Zero 1.0 1.5 2.0 19 / 35In which of the following, the Vant Hoff factor (i) is equal to one- NaCI KNO3 Urea All 20 / 35Which aqucous solution has minium freezing point – 0.01 M NaCI 0.005 M C_2H2OH 0.005 M Mgl2 0.005 M MgSO4 21 / 35Which solution will show maximum elevation in b.pt- 0.1 M KCl 0.1 M BaCl2 0.1 MFeCl3 0.1 MFe2(SO4)3 22 / 35The passing of solvent particles through semipermeable membrane is called- Osmosis Electrodialysis Electrophoresis Electroplating 23 / 35An example of colligative property is – Freezing point Boiling point Vapour pressure Osmotic pressure 24 / 35The molal elevation/depression constant depends upon- Nature of solvent Nature of solute Temperature ∆H solution 25 / 35In cold countries, ethylene glycol is added to water in the radiators of cars during winters. It results in – Lowering in boiling point Reducing viscosity Reducing specific heat Lowering in freezing point 26 / 35Which of the following is not a colligative property – ∆T_f (b) π ∆T_b K_b 27 / 35Solution distilled without change in composition at a temperature are called- Amorphous Azeotropic mixture Ideal solution Super saturated solution 28 / 35The relative lowering in vapourpressure is- ∝X_solute ∝1/X_solute = X_solute ∝m 29 / 35The amount of present in 400 ml of 0.1 M solution of the acid is- 2.45 g 3.92 g 9.080 g 4.9 g 30 / 35The units of mole fraction of a compound in solution are- mol〖Kg〗^(-1) mol 〖litre〗^(-1) 〖litre〗^(-1) None of these 31 / 35Solute when dissolve in water- Increase the vapour pressure of water Decrease the boiling of water Decrease the freezing point of water All of the above 32 / 35The number of moles present in 2 litre of 0.5 M NaOH is- 2 1 0.1 0.5 33 / 35Molarity of a solution relates the- Moles of solute and solvent Moles of solute and mass of solution Volume of solute and volume of solvent Volume of solution and moles of solute 34 / 35Calculate the vapour pressure of a solution at C containing 3g of cane sugar in33g of water. (At wt. C = 12 , H = 1 , O = 16) 760 mm Hg 756.90 mm Hg 758.30 mm Hg None 35 / 35Calculate the molarity of pure water (d=1g/l) 555 M 5.55 M 55.5 M None Your score isThe average score is 27% LinkedIn Facebook VKontakte 0% Restart quiz